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2x^2-30x=2000
We move all terms to the left:
2x^2-30x-(2000)=0
a = 2; b = -30; c = -2000;
Δ = b2-4ac
Δ = -302-4·2·(-2000)
Δ = 16900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16900}=130$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-130}{2*2}=\frac{-100}{4} =-25 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+130}{2*2}=\frac{160}{4} =40 $
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